Use the quadratic model h = -16t2+v0t+h0 to solve the following problem.
A cannonball is shot upward from the upper deck of a fort with an initial velocity of 192 feet per second. The deck is 32 feet above the ground.
Quadratic Model: h= -16t2+192t+32
How high does the cannonball go?
The cannon will go 608 feet. This is found by finding the y-coordinate of the vertex.
How long is the cannonball in the air?
-192±√(192)2-4(-16)(32) = -192±√36864+2048
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2(-16) -32
-192-197= -389
-389/-32=12.15625
The cannon ball is in the air for approximately 12.16seconds.
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